Posted by **Dee** on Sunday, November 4, 2012 at 5:29pm.

a 55g aluminum block initially at 27degrees C absorbs 725J of heat. What is the final temp.

I know I need to use the equation

q=m*Cs*Delta T but I cannot figure out how to rearrange the equation to isolate Tf to get the answer.

Thanks for any help.

- chemistry -
**DrBob222**, Sunday, November 4, 2012 at 5:41pm
My experience is NOT to try rearranging it before you subtitute. I think it is far easier to substitute, then solve the equation.

q = mass x specific heat x (Tf-Ti)

725 = 55 x specific heat Al x (Tf - 27).

What Al? about 0.3 or so J/g?

725 = 55 x 0.3 x (Tf-27)

725 = 55*0.3*Tf - (55*0.3*27)

Multiply all that stuff inside the parentheses and solve the resulting equation for Tf.

## Answer This Question

## Related Questions

- chemistry - A 45 g block of aluminum initially at 28.0° C absorbs 548 J of heat...
- Chemistry - Suppose that 1.00 g of rubbing alcohol (C3H8O) evaporates from a 57....
- CHEMISTRY - Suppose that 1.01g of rubbing alcohol(C3H8O) evaporates from a 56.0g...
- heat of vaporization - Suppose that 1.00 g of rubbing alcohol (C3H8O) evaporates...
- AP Chem - I missed a lab in class a week ago and had to make it up just the ...
- Chemistry - A 45kg sample of water absorbs 364kJ of heat. If the water was ...
- Chemistry - A block of aluminum with a volume of 98.5 cm3 absorbs 67.4 J of heat...
- Chemistry - A block of aluminum with a volume of 98.5 cm3 absorbs 67.4 J of heat...
- Chemistry I - A block of aluminum with a volume of 96.6 cm3 absorbs 66.6 J of ...
- Chemistry - Calculate the amount of heat (in calories) absorbed when 50.0g of ...

More Related Questions