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January 30, 2015

January 30, 2015

Posted by **ron** on Sunday, November 4, 2012 at 1:37pm.

- calculus -
**Steve**, Sunday, November 4, 2012 at 1:41pmif the base is x from the wall,

cosθ = x/13

-sinθ dθ/dt = 1/13 dx/dt

when x=5, sinθ = 12/13

-12/13 dθ/dt = 1/13 (2)

dθ/dt = -1/6

note the "-" sign: the angle decreases as the ladder slips down.

- calculus -
**Damon**, Sunday, November 4, 2012 at 1:50pm5, 12, 13 right triangle

call angle ladder to ground T

cos T = x/13 where x is base of ladder to base of wall

-sin T dT/dt = (1/13) dx/dt

at x = 5, t = 0, dx/dt = 5

cos T = 5/13 so T = 67.4 degrees or 1.18 radians

sin T = sin 67.4 = 12/13 = .923

-.923 dT/dt = (1/13)(2)

so

dT/dt = -.167 radians/second

times 180/pi = -9.55 degrees/second

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