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August 23, 2014

August 23, 2014

Posted by **Anonymous** on Sunday, November 4, 2012 at 11:08am.

- Math -
**Steve**, Sunday, November 4, 2012 at 1:24pmequations do not have derivatives; functions do.

for tis, use the chain rule: (e^u)' = e^u u'

y = e^(-x^2)

y' = e^(-x^2) (-2x) = -2x e^(-x^2)

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