Posted by **StressedStudent** on Saturday, November 3, 2012 at 11:17pm.

A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk at its center. Rotating flywheels provide a means for storing energy in the form of rotational kinetic energy and are being considered as a possible alternative to batteries in electric cars. The gasoline burned in a 482-mile trip in a typical midsize car produces about 3.38 x 109 J of energy. How fast would a 26.0-kg flywheel with a radius of 0.222 m have to rotate to store this much energy?

- Physics -
**Damon**, Saturday, November 3, 2012 at 11:34pm
(1/2) I w^2 = 3.38*10^9

I = (1/2) m r^2 = (1/2)(26)(.222)^2

= .641 kg m^2

(1/2) I = .320 kg m^2

so

.320 w^2 = 3.38 * 10^9

w^2 = 10.55 *10^9 = 1.055 * 10^10

w = 1.03 * 10^5 radians/s

= .163 * 10^5 revolutions/sec

= 9.81 * 10^5 rpm

981,000 rpm

forget about it. If the axis were level, you could not turn it without flipping over but no matter how strong the material it would have flown apart by then.

- Physics -
**Damon**, Saturday, November 3, 2012 at 11:40pm
I suppose you could have contra rotating flywheels pointed at each other to prevent the gyroscopic flip over problem, but you still can not get that sort of rpm practically even in a vacuum with magnetic suspension bearings without the material flying apart from centripetal acceleration stress. Something has o hold the material at the outside in toward the center and that is the radial tensile stress in the material.

- Physics -
**drwls**, Saturday, November 3, 2012 at 11:44pm
Set the rotational kinetic energy equal to 3.39*10^9 Joules, and solve for the angular velocity, w.

The rotational KE is (1/2)*I*w^2

The moment of inertia of a solid disc about the center is

I = (1/2)MR^2

- Physics -
**Damon**, Saturday, November 3, 2012 at 11:47pm
By the way, we tried this.

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