Posted by **StressedStudent** on Saturday, November 3, 2012 at 10:15pm.

A long, thin rod is cut into two pieces, one being twice as long as the other. To the midpoint of piece A (the longer piece), piece B is attached perpendicularly, in order to form the inverted “T” shown in the drawing. The application of a net external torque causes this object to rotate about axis 1 with an angular acceleration of 1.1 rad/s2. When the same net external torque is used to cause the object to rotate about axis 2, what is the angular acceleration?

- Physics -
**Damon**, Saturday, November 3, 2012 at 10:26pm
Obviously I do not know what your axes are.

lengths 2 and 1

masses 2 and 1

if along the long rod:

I = (1/3)(1) * 1^2 = 1/3

if along the short rod

I = (1/12)(2) * 2^2 = 8/12 = 2/3

if perpendicular to the plane of the rods at intersection

I = 3 (1/3) (1)(1^2) = 1 = 3/3

so angular accelerations are in the ratio 1,2,3 with the maximum being along the long rod through its center and the minimum (max I) being the last of the three

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