Posted by StressedStudent on Saturday, November 3, 2012 at 10:15pm.
Obviously I do not know what your axes are.
lengths 2 and 1
masses 2 and 1
if along the long rod:
I = (1/3)(1) * 1^2 = 1/3
if along the short rod
I = (1/12)(2) * 2^2 = 8/12 = 2/3
if perpendicular to the plane of the rods at intersection
I = 3 (1/3) (1)(1^2) = 1 = 3/3
so angular accelerations are in the ratio 1,2,3 with the maximum being along the long rod through its center and the minimum (max I) being the last of the three
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