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A long, thin rod is cut into two pieces, one being twice as long as the other. To the midpoint of piece A (the longer piece), piece B is attached perpendicularly, in order to form the inverted “T” shown in the drawing. The application of a net external torque causes this object to rotate about axis 1 with an angular acceleration of 1.1 rad/s2. When the same net external torque is used to cause the object to rotate about axis 2, what is the angular acceleration?

  • Physics -

    Obviously I do not know what your axes are.
    lengths 2 and 1
    masses 2 and 1
    if along the long rod:
    I = (1/3)(1) * 1^2 = 1/3

    if along the short rod
    I = (1/12)(2) * 2^2 = 8/12 = 2/3

    if perpendicular to the plane of the rods at intersection
    I = 3 (1/3) (1)(1^2) = 1 = 3/3

    so angular accelerations are in the ratio 1,2,3 with the maximum being along the long rod through its center and the minimum (max I) being the last of the three

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