Posted by Anonymous on Saturday, November 3, 2012 at 9:05pm.
.83 = 1(1/2)^(t/5730
.83 = .5^(t/5730)
ln .83 = (t/5730) ln .5
t/5730 = ln .83/ln .5
t = 5730(ln .83/ln .5) = appr 1540.3 years
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