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April 23, 2014

April 23, 2014

Posted by **Anonymous** on Saturday, November 3, 2012 at 9:05pm.

- math -
**Reiny**, Saturday, November 3, 2012 at 9:53pm.83 = 1(1/2)^(t/5730

.83 = .5^(t/5730)

ln .83 = (t/5730) ln .5

t/5730 = ln .83/ln .5

t = 5730(ln .83/ln .5) = appr 1540.3 years

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