Posted by **James** on Saturday, November 3, 2012 at 9:04pm.

How would I do this one?

n=1 to infinity n^n/4^1+3*n

Does it absolutely converge, conditionally converge, or diverge?

What would I do here?

- Calc 2 -
**Damon**, Saturday, November 3, 2012 at 9:29pm
n^n /[ 4^(1+3n) ] or what?

Need parentheses to see what you mean.

By the way that clearly does not converge.

- Calc 2 -
**James**, Saturday, November 3, 2012 at 9:31pm
This is how it looks: hopefully this clarifies it a bit.

n^n/(4)^1+3*n

- Calc 2 -
**Damon**, Saturday, November 3, 2012 at 9:41pm
but 4^1 is just 4

do you mean

n^n / (4 + 3n) ?

that would be for large n

n^n /3n

(1/3) n^(n-1)

which gets very large indeed

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