Posted by **James** on Saturday, November 3, 2012 at 9:04pm.

How would I do this one?

n=1 to infinity n^n/4^1+3*n

Does it absolutely converge, conditionally converge, or diverge?

What would I do here?

- Calc 2 -
**Damon**, Saturday, November 3, 2012 at 9:29pm
n^n /[ 4^(1+3n) ] or what?

Need parentheses to see what you mean.

By the way that clearly does not converge.

- Calc 2 -
**James**, Saturday, November 3, 2012 at 9:31pm
This is how it looks: hopefully this clarifies it a bit.

n^n/(4)^1+3*n

- Calc 2 -
**Damon**, Saturday, November 3, 2012 at 9:41pm
but 4^1 is just 4

do you mean

n^n / (4 + 3n) ?

that would be for large n

n^n /3n

(1/3) n^(n-1)

which gets very large indeed

## Answer this Question

## Related Questions

- Calculus 2 - n=1 series to infinity (-5^n)/n^3 does it absolutely converge, ...
- calculus - The sum from n=1 to infinity of cos(npi/3)/n! Does this absolutely ...
- math - for what values of x does the series converge absolutely and for what ...
- Calculus - For the sequences below, find if they converge or diverge. If they ...
- Calculus 2 - Does Series n=1 to infinity 1/2n+1 converge or diverge? I'm ...
- Calculus - does the series 1/(n^2+n) converge or diverge? n=2 to n=infinity
- Calculus - does the sum e^n / n! converge or diverge? n=1 --> infinity
- Calculus - does the sum 3/(2^(n)-1) converge or diverge? n=1--->infinity
- Calculus-PLZ HELP! =) - does the sum 3/(2^(n)-1) converge or diverge? n=1--->...
- Calc 2 - Does 3/4 - 3/5 + 3/6 - 3/7 + 3/8.... Converge or Diverge?

More Related Questions