n^n /[ 4^(1+3n) ] or what?
Need parentheses to see what you mean.
By the way that clearly does not converge.
This is how it looks: hopefully this clarifies it a bit.
but 4^1 is just 4
do you mean
n^n / (4 + 3n) ?
that would be for large n
which gets very large indeed
Calculus 2 - n=1 series to infinity (-5^n)/n^3 does it absolutely converge, ...
calculus - The sum from n=1 to infinity of cos(npi/3)/n! Does this absolutely ...
math - for what values of x does the series converge absolutely and for what ...
Calculus - For the sequences below, find if they converge or diverge. If they ...
Calculus 2 - Does Series n=1 to infinity 1/2n+1 converge or diverge? I'm ...
Calculus - does the series 1/(n^2+n) converge or diverge? n=2 to n=infinity
Calculus - does the sum e^n / n! converge or diverge? n=1 --> infinity
Calculus - does the sum 3/(2^(n)-1) converge or diverge? n=1--->infinity
Calc 2 - Does 3/4 - 3/5 + 3/6 - 3/7 + 3/8.... Converge or Diverge?
Calculus-PLZ HELP! =) - does the sum 3/(2^(n)-1) converge or diverge? n=1--->...