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December 19, 2014

December 19, 2014

Posted by **Anonymous** on Saturday, November 3, 2012 at 8:38pm.

- math -
**Damon**, Saturday, November 3, 2012 at 8:47pmx = Xo e^-kt

(x/Xo) = 1/2 = e^-(5730)k

ln .5 = -5730 k

-.693 =-5730 k

k = 1.21*10^-4

then

.83 = e^-1.21*10^-4 t

ln .83 = -1.21 * 10^-4 t = -.186

t = 10^4 * .154 = 1540 or 1500 years old

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