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August 31, 2015

Homework Help: calculus

Posted by travis on Saturday, November 3, 2012 at 11:51am.

f''(x) = (3x^3 - 5x^2 + 1) / x^2; and f(1) = 0, f(-1) = 1.

So i turn f''(x) into (3x^3 - 5x^2 + 1)(x^-2) and multiply to get f''(x) = 3x - 5 + x^-2

So f'(x) = (3/2)x^2 - 5x - (1/x) + c

And f(x) = (1/2)x^3 - (5/2)x^2 - ln(x) + cx + d

Not really sure what to do from here, and when plugging in -1 to ln(x) I encounter a problem. Thanks for any help

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