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November 27, 2014

November 27, 2014

Posted by **Lee** on Saturday, November 3, 2012 at 11:18am.

-6+i/-5+i

Could someone explain the steps?

- algebra -
**Steve**, Saturday, November 3, 2012 at 12:13pmrecall that (a+bi)(a-bi) = a^2+b^2

to get that pesky complex number out of the denominator, multiply by (-5-i) top and bottom:

(-6+i)(-5-i)/(-5-i)(-5+i)

= (30 - 5i + 6i - i^2)/26

= (31 + i)/26

= 31/26 + 1/26 i

- algebra -
**Lee**, Saturday, November 3, 2012 at 3:33pmthank you

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