Friday

August 29, 2014

August 29, 2014

Posted by **ladybug** on Friday, November 2, 2012 at 11:02pm.

given the function of f(x)=4x-8

a. find the the rate of change between the stated values for x:5 to 7

b. find the equation of a secant line containing the given points (5,f(5)), and (7,f(7))

Like I said I have no clue. Can you please show me how you got the answer please?

- college algebra--please -
**Steve**, Saturday, November 3, 2012 at 3:25amrate of change is (change in y)/(change in x)

f(5) = 12

f(7) = 20

y changes from 12 to 20 as x changes from 5 to 7:

rate of change is thus (20-12)/(7-5) = 8/2 = 4

Note that the rate of change is the same as the slope of the line f(x)=4x-8

The secant line is thus the line from (5,12) to (7,20). Or, it is the line from (5,12) with a slope of 4. Either way, you get

(y-12) = 4(x-5)

y = 4x -8

This is not surprising, since the secant joining any two points on a line is just a section of the same line.

It strikes me as odd that such a problem is posed. Could it be that the function is

f(x) = 4^x-8. Probably not, as the values of f(x) would be quite large.

Oh well, if the function is wrong, just use the method above to find the secant.

**Related Questions**

pre-calculas - can someone please help me with this question? Given the function...

Calculus Please Help - Given the numerical values shown for the function f(x), ...

college algebra - given the function fx=x^3+x a) find the rate of change between...

college algebra - Given the function f(x) = x^3+ 3x Find the rate of change ...

math - can someone please help me with this question. Given the funtion f(x)= 3x...

college algebra - A function is given. Determine the average rate of change of ...

college algebra - A function is given. Determine the average rate of change of ...

Math - Could someone help me with these questions, I don't know question c) and ...

college algebra - given function f(X)=X^3+3x findthe rate of change between the ...

Math~Reinyyy - Could someone help me with these questions, I don't know ...