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November 27, 2014

November 27, 2014

Posted by **zachary** on Friday, November 2, 2012 at 5:09pm.

- college algebra -
**Reiny**, Friday, November 2, 2012 at 5:33pmy = x(x+12)

so the x-intercepts are 0 and -12

and the x of the vertex must be halfway between those intercepts

x of vertex is -6

then y = 36 - 6(12) = -36

vertex is ((-6,-36), opens up, and has x-intercepts of 0 and -12

domain: obviously any value of x

range: y ≥-36

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