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September 1, 2014

September 1, 2014

Posted by **Alycia** on Friday, November 2, 2012 at 12:33pm.

((sinx + cosx)/(1 + tanx))^2 + ((sinx - cosx)/(1 - cotx))^2 = 1

- Math -
**Steve**, Friday, November 2, 2012 at 7:03pmsince there's only one side that needs manipulating, I'd pick the left side. :-)

since

1+tan = (sin+cos)/cos and

1-cot = (sin-cos)/sin

we have

[(sin+cos)*cos/(sin+cos)]^2 + [(sin-cos)*sin/(sin-cos)]^2

= sin^2+cos^2

= 1

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