Balance the following equation:
K2CrO4+Na2SO3+HCl--->KCl + Na2SO4+CrCl3+H2O
Enter the coefficients for each compound, separated by commas, in the order in which they appear in the equation (e.g., 1,2,3,4,5,6,7).
To balance the given chemical equation:
K2CrO4 + Na2SO3 + HCl ---> KCl + Na2SO4 + CrCl3 + H2O
We'll follow a step-by-step process:
Step 1: Count the number of atoms of each element on both sides of the equation.
K: 2 on the left, 1 on the right
Cr: 1 on the left, 1 on the right
O: 4 on the left, 4 on the right
Na: 2 on the left, 2 on the right
S: 1 on the left, 1 on the right
H: 1 on the left, 1 on the right
Cl: 1 on the left, 4 on the right
Step 2: Start by balancing the compounds containing the most atoms that appear on the left and right sides of the equation.
Let's start with the most complex compound, K2CrO4.
We have 2 potassium atoms (K) on the left side and 1 potassium atom (K) on the right side.
To balance the potassium, we'll put a coefficient of 2 in front of KCl.
The equation now becomes:
K2CrO4 + Na2SO3 + HCl ---> 2KCl + Na2SO4 + CrCl3 + H2O
Next, we'll balance the chromium (Cr) atom.
There is already 1 chromium atom on both sides of the equation, so it is balanced.
Step 3: Move on to balance the other elements by counting each atom one at a time.
Sodium (Na): 2 on the left, 2 on the right (balanced)
Sulfur (S): 1 on the left, 1 on the right (balanced)
Hydrogen (H): 1 on the left, 1 on the right (balanced)
Chlorine (Cl): 1 on the left, 4 on the right.
To balance the chlorine, we'll put a coefficient of 6 in front of HCl (hydrochloric acid).
The equation now becomes:
K2CrO4 + Na2SO3 + 6HCl ---> 2KCl + Na2SO4 + CrCl3 + H2O
Oxygen (O): 4 on the left, 4 on the right (balanced)
Step 4: Check if all the elements are balanced.
All the elements are now balanced.
Step 5: Simplify the coefficients (if possible).
In this case, the coefficients are already simplified.
Therefore, the balanced equation is:
K2CrO4 + Na2SO3 + 6HCl ---> 2KCl + Na2SO4 + CrCl3 + H2O
So, the coefficients for each compound, separated by commas, are:
1, 1, 6, 2, 1, 1, 1
You need to learn how to balance these redox equations yourself. Here is a site that can help. Also, ask specific questions about what you don't understand and I can help you through it.
http://www.chemteam.info/Redox/Redox.html