Saturday

February 28, 2015

February 28, 2015

Posted by **sarah** on Friday, November 2, 2012 at 7:53am.

- physics -
**drwls**, Friday, November 2, 2012 at 8:48amStart counting time t from when the drunk motorist passes. Let his distance travelled be X1 and the distance travelled by the police car be X2.

X1 = V*t

X2 = (a/2) t^2

X1 = X2 when both equal 10 km. That is when the police car catches up.

t = 10 km/(90 km/h) = 1/9 h = 6.67 minutes

You could also solve for the police car's acceleration a, but they don't ask for that.

**Answer this Question**

**Related Questions**

physics - A speeder traveling at a constant speed of 125km/h races past a ...

Math - A motorist traveling 55 mph is being pursued by a highway patrol car ...

Physics - A speeder traveling at a constant speed of 102 km/h races past a ...

Physics - A motorist traveling at 30 m/s passes a parked police car. At the ...

physics - police officer in a patrol car parked in a 70km/h zone observe a ...

Physics - A speeding motorcyclist is traveling at a constant speed of 31.1 m/s ...

physics - A speeder doing 50.0 mi/hr (about 22 m/s) in a 25 mi/hr zone ...

physics - A student driving at a constant speed of 45 m/sec passes a highway ...

Physics. - An unmarked police car traveling a constant 95 km/h is passed by a ...

Physics - An unmarked police car traveling a constant 80km/h is passed by a ...