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January 27, 2015

January 27, 2015

Posted by **mujisen** on Friday, November 2, 2012 at 5:24am.

- physic question -
**Elena**, Saturday, November 3, 2012 at 6:19amkx²/2=mv²/2

v=x•sqrt(k/m)

t=sqrt(2h/g)

s=v•t= x•sqrt(k/m) • sqrt(2h/g) =>

s1= x1•sqrt(k/m) • sqrt(2h/g)

s2= x2•sqrt(k/m) • sqrt(2h/g)

s1/s2=x1/x2

x2=x1•s2/s1 =1.1 (2.15/(2.15-0.23) =1.23 cm

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