posted by marco on .
A pelican flying along a horizontal path drops
a fish from a height of 4.7 m. The fish travels
7.7 m horizontally before it hits the water
What was the pelican’s initial speed? The
acceleration of gravity is 9.81 m/s2 .
Answer in units of m/s
d = Vo*t + 0.5g*t^2 = 4.7 m.
0 + 4.9t^2 = 4.7
t^2 = 0.9592
Tf = 0.98 s. = Fall time.
Dx = Xo * Tf = 7.7 m.
Xo * 0.98 = 7.7
Xo = 7.86 m/s. = Initial hor. speed.