Posted by Ray on Thursday, November 1, 2012 at 10:36pm.
f' = 5x^4 lnx + x^4 = x^4(5lnx + 1)
f'' = 20x^3 lnx + 5x^3 + 4x^3 = x^3(20lnx + 9)
f' = 0 at x = 0 or e^(-1/5)
f'' = 0 at x=0 or e^(-9/20)
as you know
f increasing where f' > 0
min where f'=0 and f'' not zero
concave up where f'' > 0
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