find energy of a single photon of light when you have 5.4*10^12 hertz.
energy=planck's constant* frequency
but it is in hertz
hertz is the SI unit for frequency, in fundamental units one hz=sec^-1
ok. thank u
To find the energy of a single photon of light, you can use the equation:
E = h * f
Where:
E is the energy of the photon
h is Planck's constant (approximately 6.626 x 10^-34 J · s)
f is the frequency of the photon
In this case, the frequency given is 5.4 x 10^12 Hz. To find the energy, you can substitute this value into the equation:
E = (6.626 x 10^-34 J · s) * (5.4 x 10^12 Hz)
First, multiply the numerical values:
E = (6.626 x 5.4) * (10^-34 x 10^12)
E = 35.6904 x 10^-22 Joules
Next, simplify the units by combining the powers of 10:
E = 35.6904 x 10^-22 Joules
E = 35.6904 x 10^-22 x 1 x 10^10^-9 Joules (convert from 10^-22 to 10^-9)
E = 35.6904 x 10^-31 Joules
Therefore, the energy of a single photon with a frequency of 5.4 x 10^12 Hz is approximately 35.6904 x 10^-31 Joules.