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October 25, 2014

October 25, 2014

Posted by **Alycia** on Thursday, November 1, 2012 at 4:19pm.

Problem 1. (secx/cosx)-(cscx/sinx)=tan^2x-cot^2x

Problem 2. secx+cscx=(1+tanx)/sinx

- Pre-Cal -
**Reiny**, Thursday, November 1, 2012 at 5:55pm1.

LS = (1/cosx) / cosx - (1/sinx) /sinx

= 1/cos^2 x - 1/(sin^2 x)

= (sin^2x + cos^2x)/cos^2x - (sin^2x + cos^2x)/sin^2x

= sin^2x/cos^2x + cos^2x/cos^2x - sin^2x/sin^2x - cos^2x/sin^2x

= tan^2x + 1 - 1 - cot^2x

= tan^2x - cot^2x

= RS

2. RS = (1+tanx)/sinx

= 1/sinx + tanx/sinx

= cscx + (sinx/cosx) /sinx

= cscx + 1/cosx

= cscx + secx

= LS

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