Wednesday

April 16, 2014

April 16, 2014

Posted by **Alycia** on Thursday, November 1, 2012 at 4:19pm.

Problem 1. (secx/cosx)-(cscx/sinx)=tan^2x-cot^2x

Problem 2. secx+cscx=(1+tanx)/sinx

- Pre-Cal -
**Reiny**, Thursday, November 1, 2012 at 5:55pm1.

LS = (1/cosx) / cosx - (1/sinx) /sinx

= 1/cos^2 x - 1/(sin^2 x)

= (sin^2x + cos^2x)/cos^2x - (sin^2x + cos^2x)/sin^2x

= sin^2x/cos^2x + cos^2x/cos^2x - sin^2x/sin^2x - cos^2x/sin^2x

= tan^2x + 1 - 1 - cot^2x

= tan^2x - cot^2x

= RS

2. RS = (1+tanx)/sinx

= 1/sinx + tanx/sinx

= cscx + (sinx/cosx) /sinx

= cscx + 1/cosx

= cscx + secx

= LS

**Related Questions**

pre cal - does anyone take pre-cal online ?

Integrated Physics and Chemistry - The specific heat capacity of copper is 0.09 ...

math - 80 cal/g x 5 g 400g/cal or 400 cal/g not sure can any one help Neither. ...

chemistry - How many calories are required to heat 25.0 g of platinum from 24.5...

Pre-Cal - Find the standard form of the equation of the ellipse. (Remember ...

Pre-Calculus - I am supposed to solve these conics, can you please help :)I am ...

Pre-cal - Hi, I don't understand this problem also. Find the the relative ...

Pre-Calculus - I'm trying to finish up my pre-cal homework and I am stuck on 2 ...

Pre-Calculus - I'm trying to finish up my pre-cal homework and I am stuck on 2 ...

physics - A 50 gram ice cube is cooled to -10oC in the freezer. How many ...