Wednesday

November 26, 2014

November 26, 2014

Posted by **Ashley** on Thursday, November 1, 2012 at 1:29pm.

- Physics -
**Jennifer**, Thursday, November 1, 2012 at 3:25pmF*r = I * a

Where F is the force on the merry-go-round, r is the radius, I is the moment of inertia of the merry-go-round, and a is the angular acceleration

for a solid, horizontal disk, the moment of inertia is: 1/2*m*r^2

F*r = 1/2*m*r^2*a

F = 1/2*m*r*a

w = w0 + a*t

where w is the angular speed, t is time, w0 is the initial angular speed

0.7 rev / s *(2*pi radians/rev) = 4.3 radians/s

4.3 = a*2

a = 2.2 rad/s^2

Plug this into the above equation to solve for F

- Physics -
**yesi**, Thursday, June 19, 2014 at 2:33amwrong

**Answer this Question**

**Related Questions**

PHYSICS - A 190-kg merry-go-round in the shape of a uniform, solid, horizontal ...

Physics - A 190-kg merry-go-round in the shape of a uniform, solid, horizontal ...

physics - A 346 kg merry-go-round in the shape of a horizontal disk with a ...

physics - A 175 kg merry-go-round in the shape of a uniform, solid, horizontal ...

Physics - In a playground, there is a small merry-go-round of radius 1.20 m and ...

Physics - In a playground, there is a small merry-go-round of radius 1.20 m and ...

Physics - In a playground, there is a small merry-go-round of radius 1.20 m and ...

physics - A disk-shaped merry-go-round of radius 2.63 m and mass 155 kg rotates ...

Physics - A horizontal 873 N merry-go-round of radius 1.11 m is started from ...

Physics - A playground merry-go-round made in the shape of a solid disk, has a ...