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April 23, 2014

April 23, 2014

Posted by **Ashley** on Thursday, November 1, 2012 at 1:29pm.

- Physics -
**Jennifer**, Thursday, November 1, 2012 at 3:25pmF*r = I * a

Where F is the force on the merry-go-round, r is the radius, I is the moment of inertia of the merry-go-round, and a is the angular acceleration

for a solid, horizontal disk, the moment of inertia is: 1/2*m*r^2

F*r = 1/2*m*r^2*a

F = 1/2*m*r*a

w = w0 + a*t

where w is the angular speed, t is time, w0 is the initial angular speed

0.7 rev / s *(2*pi radians/rev) = 4.3 radians/s

4.3 = a*2

a = 2.2 rad/s^2

Plug this into the above equation to solve for F

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