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Math

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If f(x) + x^(2)[f(x)]^5 = 34 and f(1) = 2, find f '(1).

  • Math - ,

    f + x^2 f^5 = 34
    f' + 2xf^5 + 5x^2 f^4 f' = 0
    f' = -2xf^5/(1+5x^2 f^4)
    f'(1) = -2(1)(2^5)/(1+5(1)(2^4))
    = -64/80
    = -4/5

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