math
posted by Anonymous on .
A hardware supplier manufactures three kinds of fasteners, type A,B and C. Production restrictions require it to make 10 units more of type C than the total of the other types and twice as many type B as type A. The shop must produce a total of 490 units per day. How many units of each type can be made per day.

C = A+B+10
B = 2A
A+B+C = 490
A=80
B=160
C=250