If you have 1.80 moles of H2, how many gram of NH3 can be produced?
Well, let's do some mole-math and turn this question into a chemistry joke!
So, we have 1.80 moles of H2. Now, imagine those moles putting on a little performance in a chemistry circus. They're flying around in their tiny hydrogen cars, doing flips, and generally being super entertaining.
Now, here's the punchline: These moles of H2 are going to react with nitrogen (N2) to produce ammonia (NH3), which is also known as a fun chemical clown!
But, to answer your question seriously (pun-intended), we need to use the balanced equation for the reaction:
3H2(g) + N2(g) → 2NH3(g)
From the equation, we can see that for every 3 moles of H2, we produce 2 moles of NH3.
So, if we start with 1.80 moles of H2, we can use the ratio from the balanced equation to calculate the moles of NH3 produced:
(1.80 moles H2) × (2 moles NH3/3 moles H2) = 1.20 moles NH3
Now, to find the grams of NH3, we need to use the molar mass of NH3, which is approximately 17 grams per mole. So:
(1.20 moles NH3) × (17 grams/mole) = 20.4 grams NH3
So, if my clown math skills are still on point, 1.80 moles of H2 will produce approximately 20.4 grams of NH3.
To determine the number of grams of NH3 that can be produced from 1.80 moles of H2, we need to consider the balanced equation for the reaction between H2 and NH3:
3H2(g) + N2(g) -> 2NH3(g)
From the balanced equation, we can see that 3 moles of H2 react to produce 2 moles of NH3.
First, we need to calculate the number of moles of NH3 produced using the given 1.80 moles of H2 by applying a mole ratio:
(1.80 moles H2) x (2 moles NH3 / 3 moles H2) = 1.20 moles NH3
Next, we can convert the moles of NH3 to grams by utilizing the molar mass of NH3, which is 17.03 g/mol:
(1.20 moles NH3) x (17.03 g NH3 / 1 mole NH3) = 20.44 g NH3
Therefore, 1.80 moles of H2 can produce approximately 20.44 grams of NH3.
To determine the number of grams of NH3 that can be produced from 1.80 moles of H2, you need to utilize the balanced chemical equation of the reaction between H2 and NH3.
The balanced chemical equation for the reaction is:
3H2 + N2 -> 2NH3
From the equation, you can see that 3 moles of H2 react to produce 2 moles of NH3.
To find the number of moles of NH3 produced, you can use the mole ratio between H2 and NH3:
1.80 moles H2 * (2 moles NH3 / 3 moles H2) = 1.20 moles NH3
Finally, to convert moles of NH3 to grams, you need to know the molar mass of NH3, which is 17.03 g/mol.
Using the formula:
Mass (in grams) = moles * molar mass
Mass of NH3 = 1.20 moles * 17.03 g/mol ≈ 20.44 grams
Therefore, approximately 20.44 grams of NH3 can be produced from 1.80 moles of H2.
Write and balance the equation.
3H2 + N2 ==> 2NH3
Using the coefficients in the balanced equation, convert mols H2 to mols NH3.
Then convert mols NH3 to g. grams = mols NH3 x molar mass NH3.