Posted by **ladybug** on Wednesday, October 31, 2012 at 9:07pm.

For the given equation list the intercepts.

Y= -2X/(X^2+1)

I think I Have this right I am not for sure?

y=-2x/(x^2+1)

(0)=(-2x/x^2+1)

-2x/x^2+1=0

-2/x+1=0

-2/x+1+0

-2/x*x+1*x=0*x

-2+x=0

x=2

y-intercept

y= -2*0/(0)^2+1

y=o/0^2+1

y=0+1

y=0/0+1

x-intercept:(2,0)

y-intercept:(0,0)

- college algebra -
**Reiny**, Wednesday, October 31, 2012 at 9:28pm
no , from your lines

-2x/x^2+1=0

-2/x+1=0

at the start you had (x^2 +1) in brackets as I just did

so when you divide top and bottom by x, every term has to be divided by x

and you would get

-2/(x + 1/x) = 0

but I would not do that

If a fraction = 0 , then the zero can only come from the numerator, and the denominator could never be zero, or else we would be dividing by zero

so in

-2x/(x^2+1) = 0

-2x = 0

x = 0

so (0,0) is both an x and a y intercept.

- college algebra -
**ladybug**, Wednesday, October 31, 2012 at 10:25pm
ok thanks

- college algebra -
**1**, Saturday, January 9, 2016 at 9:24pm
-1'

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