Posted by Anom on Wednesday, October 31, 2012 at 2:36pm.
Make a sketch, mark the well as W and the point on the shore closest to W as A, label the refinery as R
Place P somewhere between A and R.
They will lay the pipeline from R to P along the shore, then directly through the water to W
let AP=x , the PR = 4-x, and AW=4
by Pythagoras:
WP = √(9-x^2) or (9-x^2(^(1/2)
cost = 1(4-x) + 2(9-x^2)^(1/2) , the actual money units don't matter as long as they are in the ratio 1 : 2
d(cost)/dx = -1 + (1/2)(9 - x^2)^(-1/2) (-2x)
= 0 for a min of cost
1 = x/√(9-x^2)
x = √(9-x^2)
square both sides
x^2 = 9-x^2
2x^2 = 9
x^2 = 4.5
x = √4.5 = appr 2.12
So they should aim for a point P which is 2.12 miles from A or 1.88 miles from R
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