Write the formation reactions.
{You Must include the states of matter for each atom or compound}
NaClO4(s)
Na(s) + 1/2 Cl2(g) + 2O2(g) ==> NaClO4(s) is the delta H formation.
sodium hyperchloride
Well, NaClO4(s) sure looks like a fancy compound. Are you ready to be blown away by its formation reaction in all its splendor? Hold on to your seat!
Picture this: Sodium (Na), a true daredevil, decides to team up with some Chlorine (Cl) to create an explosive gang known as Sodium Chlorate (NaClO4). They gather in a solid state (s) to intimidate other atoms.
The formation reaction goes a little something like this:
Na (s) + Cl2 (g) + 4O2 (g) -> NaClO4 (s)
Isn't it marvelous how a chaotic dance of atoms can result in such a compound? Chemistry can be quite magical!
The formation reaction for sodium perchlorate (NaClO4) can be written as follows:
Na + Cl2 + 4 O2 → 2 NaClO4
In this reaction, sodium (Na) reacts with chlorine (Cl2) and oxygen (O2) to produce sodium perchlorate (NaClO4). The state of matter for each component is as follows:
Na (s) - solid
Cl2 (g) - gaseous
O2 (g) - gaseous
NaClO4 (s) - solid
The formation reaction for NaClO4(s), which is solid sodium perchlorate, can be written as follows:
Na(s) + Cl2(g) + 4O2(g) → 2NaClO4(s)
To understand how to write this formation reaction, we need to know the periodic table and the oxidation states of the elements involved. In this case, Na represents sodium, Cl represents chlorine, and O represents oxygen.
Here's how to determine the formation reaction:
1. Sodium (Na) is a Group 1 element with an oxidation state of +1, and it exists as a solid (s) in this reaction.
2. Chlorine (Cl) is a Group 17 element with an oxidation state of -1, and it exists as a gas (g) in this reaction.
3. Oxygen (O) is a Group 16 element with an oxidation state of -2, and it exists as a gas (g) in this reaction.
4. First, we balance the equation by ensuring there is an equal number of atoms of each element on both sides. Since there is only one Na on the left side, we need two Na on the right side to balance it. Similarly, since there are four O atoms on the right side, we need to balance it by having four O atoms on the left side.
5. The formation of NaClO4 involves the combination of sodium, chlorine, and oxygen. One mole of sodium reacts with one mole of chlorine gas and four moles of oxygen gas to produce two moles of sodium perchlorate.
6. Finally, we indicate the state of matter for each atom or compound. In this case, Na is a solid (s), Cl2 is a gas (g), and O2 is a gas (g). The product, NaClO4, is a solid (s).
Therefore, the formation reaction for NaClO4(s) is Na(s) + Cl2(g) + 4O2(g) → 2NaClO4(s).