Posted by Meep on Wednesday, October 31, 2012 at 11:22am.
You can try a proportional one-sample z-test for this one since this problem is using proportions.
Using a formula for a proportional one-sample z-test with your data included, we have:
z = .1 - .15 -->test value (12/120) is .1) minus population value (.15) divided by
√[(.15)(.85)/120] --> .85 represents 1-.15 and 120 is sample size.
Finish the calculation.
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