Posted by Meep on .
A local McDonald's manager will return a shipment of hamburger buns if more than 10% of the buns are crushed. A random sample of 81 buns finds 13 crushed buns. A 5% significance test is conducted to determine if the shipment should be accepted. The p value for this situation is:
0.0348
0.0500
0.0700
0.0436
0.0218

AP Statistics 
MathGuru,
You can try a proportional onesample ztest for this one since this problem is using proportions.
Using a formula for a proportional onesample ztest with your data included, we have:
z = .16  .10 >test value (13/81 is .16) minus population value (.10) divided by
√[(.10)(.90)/81] > .90 represents 1.10 and 81 is sample size.
Finish the calculation. Use a ztable to determine the pvalue for the ztest statistic.