posted by Chelsea on .
An object of mass 26 kg is thrown straight upwards from the ground at 27 m/s. Due to air resistance (a non-conservative force), the object loses some of its initial energy during its trip to reach maximum height and only travels to a height above the ground of 16.3 meters. What percentage of its initial energy is lost to air resistance during its flight to maximum height?
Without air resistance
h=v²/2g =27²/2•9.8 = 37.2 m
(mgh-mgh1)/mgh = (h-h1)/h= (37.2-16.3)/37.2=0.56