two horizontal forces F1 and F2, acting on an object of mass 1.11kg. The magnitude of F1 is 27.56N. The object moves strictly along the horizontal x-axis, which we choose as positive to the right. Find the magnitude of F2 if the object has a horizontal acceleration of 8.4m/s^2.

b). What is the magnitude of F2 if the object has a horizontal acceleration of 0m/s^2?

c). What is the magnitude of F2 if the object has a horizontal acceleration of -9.30m/s^2?

(a) ma=F1+F2 =0

F2=F1 = 27.56 N
(b)ma=F1+F2
1.11•(-9.3) = 27.56 +F2
F2= -37.883 N

for b, switch the negative to positive. F2 is in the negative direction so the negative on your answer and the negative on F2 cancel

To solve this problem, we will use Newton's second law of motion:

F = ma

Where:
F is the net force acting on the object,
m is the mass of the object, and
a is the acceleration experienced by the object.

a) Given that the object has a horizontal acceleration of 8.4 m/s^2 and a mass of 1.11 kg, we can substitute these values into our equation:

F = m * a
F = 1.11 kg * 8.4 m/s^2
F = 9.3144 N

Therefore, the magnitude of F2 is 9.3144 N when the object has a horizontal acceleration of 8.4 m/s^2.

b) If the object has a horizontal acceleration of 0 m/s^2, it means that there is no net force acting on the object horizontally. In this case, F1 and F2 cancel each other out. Therefore, the magnitude of F2 will be equal to the magnitude of F1:

F2 = F1 = 27.56 N

Therefore, the magnitude of F2 is 27.56 N when the object has a horizontal acceleration of 0 m/s^2.

c) If the object has a horizontal acceleration of -9.30 m/s^2, it means the object is accelerating in the opposite direction to our chosen positive x-axis. In this case, the net force acting on the object will be the sum of F1 and F2, but with opposite signs. Substitute the given values into our equation:

F = m * a
F = 1.11 kg * (-9.30 m/s^2)
F = -10.293 N

Since F1 is in the positive x-axis direction, F2 must be in the opposite direction to provide the net force required. Therefore, the magnitude of F2 is:

|F2| = |-10.293 N| = 10.293 N

Therefore, the magnitude of F2 is 10.293 N when the object has a horizontal acceleration of -9.30 m/s^2.