Posted by matthias on Wednesday, October 31, 2012 at 12:15am.
find an equation of the tangent line to the graph of y=e^(2x3) at point (3/2,1)
thanks!

math  Steve, Wednesday, October 31, 2012 at 10:51am
y'(x) = 2e^(2x3)
y'(3/2) = 2
so, you want the line through (3/2,1) with slope 2:
y1 = 2(x3/2)