Posted by **Cynthia** on Tuesday, October 30, 2012 at 11:51pm.

1. Locate the absolute extrema of the function f(x)=cos(pi*x) on the closed interval [0,1/2].

2. Determine whether Rolle's Theorem applied to the function f(x)=x^2+6x+8 on the closed interval[-4,-2]. If Rolle's Theorem can be applied, find all values of c in the open interval (-4,-2) such that f'(c)=0.

3. Determine whether the open intervals on which the graph of f(x)=-7x+7cosx is concave upward or downward.

4. Find the points of inflection and discuss the concavity of the function f(x)=sinx-cosx on the interval (0,2pi)

5.Find the points of inflection and discuss the concavity of the function f(x)=-x^3+x^2-6x-5

- Calculus -
**Steve**, Wednesday, October 31, 2012 at 10:38am
1.

f' = -pi sin(pi*x) extrema where f' = 0, or x an integer

2.

since f(x) = (x+4)(x+2) f(-4)=f(-2)=0, so we're good to do. vertex is at x = -3.

3.

f is concave up if f'' > 0

f'' = -7cosx, so where is that >0? <0?

4.

concavity as above, inflection where f'' = 0

f'' = -sinx + cosx = √2 sin(x + π/4)

5.

same methods as in #3,4/

f'' = -6x

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