posted by Anonymous .
A 46.4-N force is applied to the outer edge of a door of width 1.26 m in such a way that it acts (a) perpendicular to the door (b) at an angle of 43.0 degrees with respect to the door surface, (c) so that the line of action of the force passes through the axis of the door hinges. Find the torque for these three cases
(a) M= F•W =46.6•1.26 = ...
(b) M= F•W•sinα =46.6•1.26 •sin43°=