Tuesday

September 30, 2014

September 30, 2014

Posted by **Ms. Jackie** on Tuesday, October 30, 2012 at 9:29pm.

(a) log6b(6b)

(b)log8b((8b)^6)

(c)log11b((11b)^-9)

- Math -
**Steve**, Tuesday, October 30, 2012 at 10:00pmby definition logx(x) = 1 because x^1 = x

log6b(6b) = 1

log8b((8b)^6) = 6*log8b(8b) = 6*1 = 6

similarly,

log11b((11b)^-9) = -9

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