The length of a rectangular playground exceeds twice its width by 25 meters, The perimeter of the playground is 650 meters. Find the demensions of the playground.

2(x) + 2(2x + 25) = 650

x = 100
width = 200
length = 225
area = 22500

225

To find the dimensions of the rectangular playground, we can set up two equations based on the given information. Let's assign variables to represent the width and length of the playground.

Let's assume that the width of the playground is represented by 'w' meters.

According to the problem, the length exceeds twice the width by 25 meters, which means the length can be represented by the equation: 2w + 25.

The perimeter of a rectangle is given by the formula:
Perimeter = 2(length + width).

So, we can set up the equation:

650 = 2(w + (2w + 25))

Simplifying this equation will help us find the value of 'w', which represents the width.

650 = 2(3w + 25)
650 = 6w + 50
600 = 6w
w = 100

Now that we have found the width, we can substitute this value back into the equation for the length:

Length = 2w + 25
Length = 2(100) + 25
Length = 200 + 25
Length = 225

Therefore, the dimensions of the rectangular playground are:
Width = 100 meters
Length = 225 meters

x = width

2x + 25 = length

Equation:
2(x) + 2(2x + 25) = 650

Solve for x. Remember to include both length and width in your answer.

Which makes the answer 22500 as x = 100

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