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November 29, 2014

November 29, 2014

Posted by **Anonymous** on Tuesday, October 30, 2012 at 8:17pm.

- Physics -
**Jennifer**, Tuesday, October 30, 2012 at 8:50pmThe rotational kinetic energy of one wheel is

1/2 * I * w^2

where I is the moment of inertia of the wheel, w is the angular speed of the wheel.

The total kinetic energy of the system is the sum of the rotational kinetic energies of each wheel, plus the translational kinetic energy of the bicycle:

K = 1/2*I*w^2 + 1/2*I*w^2 + 1/2 *m*v^2

v = w^2*r^2

where v is the translational speed of the bicycle, and r is the radius of the bicycle's tire

K = I*w^2 + 1/2*m*w^2*r^2

the fraction is (I*w^2) / (1/2*m*w^2*r^2)

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