March 30, 2017

Post a New Question

Posted by on .

A 4.47 g sample of a molecular compound is dissolved in 96 g of tetrachloromethane. The normal boiling point of the solution is 61.51 degrees celcius, the normal boiling point for CCl4 is 61.2 degrees celsius. The boiling point constant for CCl4 is 4.95K*kg/mol. What is the molar mass of the compound? Answer in units of g/mol

I know you have to use the formula:
delta Tb = iKbm but I have no clue how start or find the molality.


  • ap chemistry - ,

    Note the correct spelling of celsius.

    Why don't you start with delta T = i*Kb*m
    You can calculate delta T, i = 1 since it is a molecular compound, you know Kb and solve for m.
    Then m = mols/kg solvent. You know m and kg solvent, solve for mols.
    Then mols = grams/molar mass. You know mols and grams, solve for molar mass.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question