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October 25, 2014

October 25, 2014

Posted by **Jane** on Tuesday, October 30, 2012 at 4:57pm.

- Algebra -
**Steve**, Tuesday, October 30, 2012 at 5:14pmIf the slow train's speed is s, then recall that time = distance/ speed:

220/s = 220/(2s) + 2

s = 55

so, the slow train travels 55 mph, the fast 110 mph.

slow takes 220/55 = 4 hours

fast takes 220/110 = 2 hours, arriving 2 hours earlier

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