How many atoms are there in the following problems?
which one has the most number of atoms?
a. 5 molecuels (NH4)2S
b. 9 molecules H2O2
c. 11 molecules O3
You can add these up. a has 11 atoms in 1 molecule. b has 4 atoms in 1 molecule. etc.
To determine the number of atoms in each of the given compounds, we need to count the number of each type of atom and multiply it by the number of molecules. Let's calculate it step by step:
a. (NH4)2S:
- The compound contains 2 ammonium ions, (NH4)2, and 1 sulfide ion, S.
- Each ammonium ion consists of 1 nitrogen atom (N) and 4 hydrogen atoms (H).
- So, in total, we have: 2(NH4) + 1S = 2(N * 1 + H * 4) + 1S = 2N2H8 + 1S.
Note: To simplify the calculations, we will consider (NH4)2 as a whole ammonium group.
b. H2O2:
- The compound has 2 hydrogen atoms (H) and 2 oxygen atoms (O) per molecule.
- So, in total, we have: 9(H2O2) = 9(H * 2 + O * 2) = 18H + 18O.
c. O3:
- The compound contains 3 oxygen atoms (O) per molecule.
- So, in total, we have: 11(O3) = 11(O * 3) = 33O.
Now, let's compare them:
a. (NH4)2S has 2N2H8 + 1S = 2 * 2 + 8 * 2 + 1 = 17 atoms.
b. H2O2 has 18H + 18O = 18 + 18 = 36 atoms.
c. O3 has 33O = 33 atoms.
Comparing the number of atoms:
- (NH4)2S has 17 atoms.
- H2O2 has 36 atoms.
- O3 has 33 atoms.
Therefore, H2O2 has the most number of atoms with 36 atoms.