Posted by Vanilla Bear on .
How do you make an equation that's perpendicular to the equation y=x+5? The given points are (3,3)
Please help and explain step by step thank you!

Algebra I 
Steve,
slopes of perpendicular lines multiply to give 1.
slope of y=x+5 is 1
slope of perpendicular line is thus 1
so, you want a line with slope 1 through (3,3).
Pull out your pointslope form of the line:
y+3 = 1(x3)
y = x