Posted by Vanilla Bear on .
How do you make an equation that's perpendicular to the equation y=x+5? The given points are (3,-3)
Please help and explain step by step thank you!
Algebra I -
slopes of perpendicular lines multiply to give -1.
slope of y=x+5 is 1
slope of perpendicular line is thus -1
so, you want a line with slope -1 through (3,-3).
Pull out your point-slope form of the line:
y+3 = -1(x-3)
y = -x