Posted by **Vanilla Bear** on Monday, October 29, 2012 at 10:02pm.

How do you make an equation that's perpendicular to the equation y=x+5? The given points are (3,-3)

Please help and explain step by step thank you!

- Algebra I -
**Steve**, Monday, October 29, 2012 at 10:59pm
slopes of perpendicular lines multiply to give -1.

slope of y=x+5 is 1

slope of perpendicular line is thus -1

so, you want a line with slope -1 through (3,-3).

Pull out your point-slope form of the line:

y+3 = -1(x-3)

y = -x

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