Posted by Ashlee on Monday, October 29, 2012 at 8:35pm.
...........CaF2(s) ==> Ca^2+ + 2F^-
I..........solid........0.......0
C..........solid........x.......2x
E..........solid........x.......2x
Ksp = (Ca^2+)(F^-)^2
Substitute from the ICE chart and solve for x. The question asks for solubility of CaF2. You will calculate x = (Ca^2+) in moles/L but since 1 mol CaF2 dissolves to give 1 mol Ca&2+, then x is also solubility CaF2.
If NaF is added to the solution what happens? Remember Le Chatelier's Principle which says that a system at equilibrium will try to undo what we do to it. So if we add F^-, the reaction will try to get rid of it. How can it do that. Only one way. That's by shifting to the left so that the solubility of CaF2 is decreased.
If we make the (F^-) = 0.1 M, then
Ksp = (Ca^2+)(F^-)^2
Ksp = (x)(0.1).
Solver for x.
what is the name for CaF2 in chemistry?
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