brakes are applied in bringing in a 1200-kg car moving at 25 m/s to rest in 20.0 s. show that the amount of braking force is 1500n.
fjyfhv
To calculate the amount of braking force applied to the car, we can use Newton's second law of motion, which states that the force (F) applied to an object is equal to its mass (m) multiplied by its acceleration (a):
F = m * a
In this case, the car is being brought to rest, so its final velocity (v) is 0 m/s. The initial velocity (u) is given as 25 m/s, and the time taken (t) is 20.0 s. We can calculate the acceleration using the equation:
a = (v - u) / t
Substituting the values into the equation:
a = (0 - 25) / 20.0
a = -25 / 20.0
a = -1.25 m/s^2
Note that the negative sign indicates that the acceleration is in the opposite direction to the initial velocity.
Now, we can calculate the braking force (F) using the equation:
F = m * a
Substituting the values into the equation:
F = 1200 kg * (-1.25 m/s^2)
F = -1500 N
The negative sign indicates that the force is in the opposite direction to the motion of the car. However, force is generally considered a scalar quantity, so we take the magnitude of the force as:
|F| = 1500 N
Therefore, the amount of braking force applied to the car is 1500 N.