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Posted by on Monday, October 29, 2012 at 3:54pm.

what is the equation in standard form of a parabola that contain the following points?
(-2,-20),(0,-4),(4,-20)
Please Help

  • algebra - , Monday, October 29, 2012 at 4:27pm

    you can probably save some time by looking at the points. You know that parabolas are symmetric, so, since y(-2) = y(4), the axis of symmetry is at x=(-2+4)/2 = 1.

    So, with x=1 the axis of symmetry (and hence at the vertex), you will have

    y = a(x-1)^2+k
    at x=0, y= -4, so
    -4 = a+k
    -20 = 9a + k

    k=-2
    a=-2

    so, y = -2(x-1)^2 - 2
    or, y = -2x^2 + 4x - 4

    ------------------------------

    or, if you let y = ax^2 + bx + c,

    -20 = 4a - 2b + c
    -4 = c
    -20 = 16a + 4b + c

    a = -2
    b = 4
    c = -4

    y = -2x^2 + 4x - 4

  • algebra - , Monday, October 29, 2012 at 4:41pm

    Thanks for helping I have posted two other questions if you might be able to help

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