Posted by Kendra on Monday, October 29, 2012 at 3:37pm.
solve for x
e^(2x+3) 7=0
ln(52x)=3

Calculus  Steve, Monday, October 29, 2012 at 3:39pm
e^(2x+3) = 7
2x+3 = ln7
x = (ln7  3)/2
ln(52x) = 3
52x = e^3
x = (5  e^3)/2
Posted by Kendra on Monday, October 29, 2012 at 3:37pm.
solve for x
e^(2x+3) 7=0
ln(52x)=3
e^(2x+3) = 7
2x+3 = ln7
x = (ln7  3)/2
ln(52x) = 3
52x = e^3
x = (5  e^3)/2