Posted by David on Monday, October 29, 2012 at 3:29pm.
There are a couple ways to do this but both depend upon the same process.
#1 way.
a) Use n = individual mols listed in the problem, use PV = nRT and solve for Peach as pN2, pH2, pCH4.
b) Then find ptotal = pN2 + pH2 + pCH4.
#2 way.
a. Add mols of individual gases to find ntotal, the use PV = nRT and substitute the conditions of the problem; solve for Ptotal (since you used ntotal).
b. Calculate mols fraction of each gas.
You know total mols from above,
XN2 = (pN2/total mols) = ?
XCH4 = (pCH4/total mols) = ?
XH2 = (pH2/total mols)
c. pH2 = XH2*Ptotal
pN2 = XN2*Ptotal
pCH4 = XCH4*Ptotal
#1 is easier because it's all the same formula; #2 is more interesting because you use something different. Mole fraction is important.
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