Posted by **Mat** on Monday, October 29, 2012 at 3:08pm.

A diver runs and dives off the end of a spring board that is 0.9 meters above the surface of the water. As she takes off from the diving board, her velocity is 5.2 m/s directed 36° above horizontal calculate:

a) the time she is in the air

s

b) the distance she lands from the board (measured horizontally from the end of the board) m

c) the maximum height she attains above the surface of the water

m

- physics -
**Steve**, Monday, October 29, 2012 at 3:34pm
the velocity v comprises x- and y- components:

vx = 5.2 cos36° = 4.2

vy = 5.2 sin36° = 3.1

y = 0.9 + 3.1t - 4.9t^2

y=0 when t=0.85

so, she is in the air 0.85 seconds

x = 4.2t

4.2(0.85) = 3.57m

so, she lands 3.57m from the end of the board.

y is max when t = -3.1/-9.8 = 0.32

y(.32) = 1.39

max height is thus 1.39m above the water

## Answer This Question

## Related Questions

- Physics - At the local swimming pool, the diving board is elevated h = 7.5 m ...
- physics - A diver runs horizontally off the end of a diving board with an ...
- Physics - A diver runs horizontally off the end of a diving board with an ...
- Physics - A diver (mass = 75.0 kg) walks to the end of a flexible diving board. ...
- AP Physics - A 45 kg gymnast steps off a platform located 1.3 m above a spring ...
- physics - Consider a case in which a 60 kg diver takes off from a diving board ...
- URGENT PHYSICS - Consider a case in which a 60 kg diver takes off from a diving ...
- Physics - A swimmer runs horizontally off a diving board with a speed of 3.14 m/...
- physics 2 HELP PLEASE!! - Can someone help break this down.. Please tell me if ...
- Physics - A 50.0 kg diver steps off a diving board and drops straight down into ...

More Related Questions