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April 20, 2014

April 20, 2014

Posted by **Mat** on Monday, October 29, 2012 at 3:08pm.

a) the time she is in the air

s

b) the distance she lands from the board (measured horizontally from the end of the board) m

c) the maximum height she attains above the surface of the water

m

- physics -
**Steve**, Monday, October 29, 2012 at 3:34pmthe velocity v comprises x- and y- components:

vx = 5.2 cos36° = 4.2

vy = 5.2 sin36° = 3.1

y = 0.9 + 3.1t - 4.9t^2

y=0 when t=0.85

so, she is in the air 0.85 seconds

x = 4.2t

4.2(0.85) = 3.57m

so, she lands 3.57m from the end of the board.

y is max when t = -3.1/-9.8 = 0.32

y(.32) = 1.39

max height is thus 1.39m above the water

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