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January 30, 2015

Posted by **Lee** on Monday, October 29, 2012 at 2:12pm.

f(x)=a(x-h)^2+k

I believe h=-4

k=7

Not sure what to do from here.

- algebra -
**Steve**, Monday, October 29, 2012 at 2:25pmfrom the vertex, you know that

y = a(x+4)^2 + 7

Now just plug in (-3,8) to find a:

8 = a(1)+7

1 = a

y = (x+4)^2 + 7

- algebra -
**Lee**, Monday, October 29, 2012 at 3:21pmI'm not sure what your saying

- algebra -
**Steve**, Monday, October 29, 2012 at 3:23pmyou seemed to be able to figure out h and k for the vertex, so what's the hangup? All I did was use your equation and use the values x=-3 and y=8 to solve for a.

- algebra -
**Lee**, Monday, October 29, 2012 at 3:53pmy=a(x-h)^2+k

y=a(x+4)^2+7

8=a((x-3)+4)^2+7

8=a(1)^2+7

1=a

4=(x+4)^2+7

Is this right?

- algebra -
**Steve**, Monday, October 29, 2012 at 4:08pmwell, I'd say yes, since it agrees with the equation I posted above. (sort of; not sure what the 4 means)

- algebra -
**Lee**, Monday, October 29, 2012 at 4:33pmsorry was y we have to show our steps when figuring problems thank you

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