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March 5, 2015

March 5, 2015

Posted by **Matt** on Monday, October 29, 2012 at 1:18pm.

A) Find the maximum altitude reached by the rocket.

B) Find the total time the rocket is in flight (up and down)

- phyicis -
**Steve**, Monday, October 29, 2012 at 3:11pmduring burn:

v = 8.2t

v(5) = 41 m/s

h = 1/2 (8.2) t^2

h(5) = 102.5 m

So, after 5 seconds, the rocket is 102.5 meters up, with a speed of 41.0 m/s.

Now, only gravity provides acceleration, so

h = 102.5 + 41.0t - 4.9 t^2

h=0 when t = 10.382

max h when t = -41.0/-9.8 = 4.18

h(4.18) = 188.265

So, the rocket reaches a max height of 188.27m after 4.18 seconds of ballistic flight, and hits the ground again after 5.0+10.382 = 15.382 seconds have elapsed.

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