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September 17, 2014

September 17, 2014

Posted by **Zach** on Monday, October 29, 2012 at 9:10am.

What is the weight of the box?

What force is needed to start the box moving?

What force is needed to keep the box moving at a constant velocity of 0.5m/s?

Once the box is moving what force must be applied to accelerate the box 2.5m/s/s?

- Physics -
**Henry**, Tuesday, October 30, 2012 at 4:54pma. Wb=m*g = 88kg * 9.8N/kg = 862.N.=Wt. of box.

Fb = 862.4 N. @ 0o. = Force of box.

Fp = 862.4*sin(00 = 0. = Force parallel to floor.

Fv = 862.4*cos(0) = 862.4 N. = Force perpendicular to floor.

Fs = u*Fv = 0.23*862.4 = 198.4 N.=Force

of static friction.

Fk = u*Fv = 0.12 * 862.4 = 103.5 N. =

Force of kinetic friction.

b. Fn = Fap-Fp-Fs = m*a.

Fap-0-198.4 = 88*0 = 0

Fap = 198.4 N. = Force applied to start

box moving.

c. Fn = Fap-Fp-Fk = m*a

Fap-0-103.5 = 88*0 = 0

Fap = 103.5 N. = Force applied to keep

box moving.

d. Fap-Fp-Fk = m*a.

Fap-0-103.5 = 88*2.5 = 220

Fap = 220 + 103.5 = 323.5 N.

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